tatic/chunks/28117-eec15bad5fdfb33c.js","50032","static/chunks/50032-b8fcf41dc4fb3788.js","61717","static/chunks/61717-cb0e9fa08a934cfc.js","59254","static/chunks/59254-931d346758c67347.js","83169","static/chunks/83169-16ff746d7998be43.js","30598","static/chunks/30598-3728c6a907b0d1f4.js","35243","static/chunks/35243-51da85fc2282ee1a.js","5322","static/chunks/5322-8a2230dab0476b06.js","22994","static/chunks/22994-0650b90a0e4aeae0.js","31168","static/chunks/31168-335fb34c44d64d28.js","76986","static/chunks/app/(unauthorized-user)/testing/%5BexamType%5D/%5B...slug%5D/page-33064de50a53f5a9.js"],"TaskSingleWrapper"] 54:I[72972,["86401","static/chunks/363642f4-e89e317e43934d85.js","65878","static/chunks/65878-41dc59acd7c08ecc.js","72972","static/chunks/72972-5b73ae53667b8052.js","80605","static/chunks/80605-b9a5b89980b52003.js","1924","static/chunks/1924-0d0ca09038c6e8f6.js","28117","static/chunks/28117-eec15bad5fdfb33c.js","50032","static/chunks/50032-b8fcf41dc4fb3788.js","61717","static/chunks/61717-cb0e9fa08a934cfc.js","59254","static/chunks/59254-931d346758c67347.js","83169","static/chunks/83169-16ff746d7998be43.js","30598","static/chunks/30598-3728c6a907b0d1f4.js","35243","static/chunks/35243-51da85fc2282ee1a.js","5322","static/chunks/5322-8a2230dab0476b06.js","22994","static/chunks/22994-0650b90a0e4aeae0.js","31168","static/chunks/31168-335fb34c44d64d28.js","76986","static/chunks/app/(unauthorized-user)/testing/%5BexamType%5D/%5B...slug%5D/page-33064de50a53f5a9.js"],""] 53:T65c,

$\circledast5x-21\ne0\Leftrightarrow x\ne\frac{21}5$

Пусть $t=\frac{10}{5x-21}$

${(t+\frac1t)}^2-\frac{25}4\le0$

Применим $a^2-b^2=(a-b)(a+b)$

$(t+\frac{1}{t}-\frac{5}{2})(t+\frac{1}{t}+\frac{5}{2})\leq0\Leftrightarrow\left[\begin{matrix}t+\frac1t-\frac52=0\mid\cdot2t\\t+\frac1t+\frac52=0\mid\cdot2t\end{matrix}\right.\Leftright</article></body></html>$

Задание №4190 ЕГЭ по Математике